19-4x^2-36x=0

Solution for 19-4x^2-36x=0 equation:

19-4x^2-36x=0

a = -4; b = -36; c = +19;
Δ = b2-4ac
Δ = -362-4·(-4)·19
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-40}{2*-4}=\frac{-4}{-8}
=1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+40}{2*-4}=\frac{76}{-8}
=-9+1/2
$